@psychonaut so your calculating a 2” x 2” puck under 1777psi on the gauge is 1000 psi on the puck?
You also mentioned to keep the gauge at 600-800psi ?
Im a bit confused around sonFor hash you recommend 1777psi at the gauge or 600/800psi? I would probably feel it out anyway but curious about what to look for roughly on the gauge cheers
I know it's confusing. Basically the pressure gauge is measuring the pressure inside the hydraulic system, the cylinder's effective area (2.25) is the bit of math that actually translates the pressure in the line to the actual pressure delivered by the cylinder.
So in order to have an idea of how much PSI you are applying on the bag, you need to know the puck size. Otherwise you're only measuring the total force based on the gauge reading and the cylinder effective area.
So we have to break it all down, and having predetermined puck sizes such as what we get when we use a pre-press mold, we know, prior to pressing, what the puck size will be. Our 30mm pre-press mold generally will squish down a puck about 1.75-2" diameter. So to use that as an example, 1.75" diameter puck is 2.4 sq/in.
Alright, so we know the puck is gonna be 2.4 sq/in, and we wanna apply 1000 PSI to that. We need 2400 total pounds of force. Ok, so to reach 2400 total pounds of force we have to divide 2400 / 2.25 = 1066 PSI on gauge.
So long as you know your surface area of your puck, you basically just do this math -
PSI desired x puck size in sq/in = total force needed
total force needed / 2.25 = Pressure on gauge
1000 x 2.4 = 2400 total force needed
2400 / 2.25 = 1066 PSI on gauge
Square/rectangle pucks are easier math, L" x W" = sq/in
Ex. 8 sq/in puck (2x4")
1000 x 8 = 8000 total force needed
8000 / 2.25 = 3555 PSI on gauge
Last edited: