The actual chemical reaction occurring during vaporization of THC

OF

Well-Known Member
@OF, there's so many different medically active cannabinoids, you don't think that the ratio of these cannabinoids could change when heat is applied? If so, would this be a chemical change? Or is the strain the only factor in determining these ratios, making them fixed (as long as grow conditions are optimal)?
:hmm::huh::smug:

Yes, I believe that, don't you? Much different than blazing. Check out the pie charts here:
http://mcrlabs.com/wp-content/uploads/2014/07/White-Paper-Vape-Ex.pdf

Most of the cannabinoids are similar in mass and structure and have similar heat of vaporization numbers so the 'pounds evaporated per BTU of heat applied' is about the same. That is while those folks got a uniform .3 mg of cannabinoids per hit, but the make up of the hit (ratio of parts) shifts to heavier stuff (higher boiling points). This is not a chemical reaction, no bonds are changed, only phase state changes, completely reversible and in fact an equilibrium situation so there are molecules cooling liquid while others (more) are evaporating to vapor.

Turn up the fire on the teapot, the water doesn't get any hotter, the only change is the rate of boil off. Same in the vape. You make vapor until you run out of hot.

There is also an honest to goodness chemical reaction going on, stripping a COOH (?) off the part of the THC 'family' to make it more active, but that happens at a lower temperature (like the 225 degrees you bake brownies at?

Yes, the starting quantities are set by genetics and upbringing......just like you and I. The rest is just a machine for extracting what comes from the grow, hopefully damaging as little of the treasure as possible.

Regards,

OF
 
OF,
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