Riddle me this - if cannabis testing lab results can vary up to 20%+, if 10g of flower DOESN'T yield 2g of pure crystalline THC, how do we know it was 20% potency to begin with?
i'll answer later.
but this:
20% percent is not a number I question.
I argue that it is 20% of the cannabinoid distribution in the trichomes. 20% off that.
A trichome is loaded with compounds.
One of them is THC.
Not 20% of the bud weight.
I mean, just look at a very frosty bud like the one posted above.
Do you really think that 1/5 of a bud like this ground up is pure thc ?
Not even 20% of this weight are trichomes .
And trichomes weight is not equal to THC weight (content)
THC is a molecule. very very tiny.
again, check the mol mass of THC
I think a testbud is grinded to powder.
then its hydrolytical processed to rid off all unbound water.
Next step resolves most organic plant matter like empty chlorophyll-cells.
What you are left with is a oily mass (thc is an acid aswell)
all compounds get analysed and weighted.
20% of that weight could be THC.
Insight from a breeder or a testlab would be helpful here.
but c'mon 20% weight of a nug are THC molecules?!
never ever.
again, the question is: 20% of
what ?
if 1g great bud can be rosin squished into 200mg rosin (thats 20%), if.
than this 200mg would not consist of pure THC.
so we would have 200mg oily residue.
A mix of various compounds. mainly oils.
THC is one of them.
It cant account to the whole amount.
ergo: 1000mg Bud cant contain 200mg THC molecules or fatty acids.
the 200mg (20%) would be the amount the THC is solved in. With many many stuff together.